Sunday, October 10, 2021
Friday, April 23, 2021
University Physics Volume 3 - 1.3 Refraction - EXAMPLE 1.2
EXAMPLE 1.2
Determining the Index of Refraction
Find the index of refraction for medium 2 in Figure (a), assuming medium 1 is air
and given that the incident angle is
°
and the angle of refraction is
°.
You can change angles and the result will be calculated for your angles.
Strategy
The index of refraction for air is taken to be 1 in most cases (and up to four significant figures, it is 1.000). Thus, n₁ = 1.00 here. From the given information, θ₁ = ° and θ₂ = °.
With this information, the only unknown in Snell’s law is n₂, so we can use Snell’s law to find it.
Solution
From Snell’s law, we have
n₁ sin θ₁ = n₂ sin θ₂
Determining the Index of Refraction
Find the index of refraction for medium 2 in Figure (a), assuming medium 1 is air
and given that the incident angle is
°
and the angle of refraction is
°.
You can change angles and the result will be calculated for your angles.
Strategy
The index of refraction for air is taken to be 1 in most cases (and up to four significant figures, it is 1.000). Thus, n₁ = 1.00 here. From the given information, θ₁ = ° and θ₂ = °.
With this information, the only unknown in Snell’s law is n₂, so we can use Snell’s law to find it.
Solution
From Snell’s law, we have
n₁ sin θ₁ = n₂ sin θ₂
n₂ = n₁ sinθ₁ / sinθ₂.
Entering known values,
n₂ = 1.00 sin ° / sin ° = / =

Entering known values,
n₂ = 1.00 sin ° / sin ° = / =

Saturday, April 17, 2021
What is C?
The angular frequency of the oscillations in an LC circuit is .0×103 rad/s.
If L= H, what is C?
Solution:
C=µC
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